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Can someone explain this code to me....
class ReverseNumberDemo
{ public static void main(String args[]) {
int num=123456789;
int reversenum =0;
while( num != 0 ) {
reversenum = reversenum * 10;
reversenum = reversenum + num%10;
num = num/10; }
System.out.println("Reverse of specified number is: "+reversenum);
}
}
the thing I don't get is the reversenum part......isn't reversenum=0 so wouldn't reversenum*10=0
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nums = [i**2 for i in range(5)]
print(nums)
[1, 4, 9, 16]
"..what will this create..?"
"Correct" answer was:
"A list of even numbers between 0 and 18."
9 is not an even number tho.
Is this a typo or am i missunderstanding/missinterpreting?
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3 ответов
explanation plzzzz!!!
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Printing pattern with Javascript
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1 ответ
In the continue Loop -
i = 0
while True:
i = i +1
if i == 2:
print("Skipping 2")
continue
if i == 5:
print("Breaking")
break
print(i)
print("Finished")
It shows the output being
"1
Skipping 2
3
4
Breaking
Finished"
Why are the last three lines not
"Breaking
5
Finished"
Where it shows print(i) after break?
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