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why this output 2 not 3 ? #include <iostream> using namespace std; int main() { int x=1; x=x++; cout<<++x; }
5 ответов
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@Josyah: The second part is not really true.
Anyways the code is executed in the following order:
1. x is set to 1 (x=1)
2. the value of x is incremented to 2 (x++)
3. a temporary variable with the xs original value of 1 is returned (x++)
4. x is assigned the temporary variable that is 1 (x=)
5. x is incremented to 2 (++x)
6. the value of x is returned (++x)
7. the value is outputted (cout <<)
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x = x++ is the same as just putting x++. And cout << ++x is printing x before it is iterated once more
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Yes, your correct. I had them backwards not paying attention. Thanks for point that out, i dont use ++val that often
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@Josyah: No prob, I rectified an ordering mistake that did not have any influence on the outcome and hopefully improved the formulation.
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thanks Stefan