Take input of three numbers and find largest number by using nested if condition.Is it correct??

Question

#include <iostream>
using namespace std;

int main() {
int x,y,z;
cin>>x>>y>>z;
if(x<z){
if(y<z){
cout<<"The largest number is "<< z;
}
}
else{
cout<<"wrong";
}
return 0;
}

Answer 1

Zoya

Compare x with y and x with z
If both returns true then x will be largest

Otherwise compare y with z

If y is greater than z then y is largest otherwise z is largest

Answer 2

What if x is greater than z output would be "wrong"?

Answer 3

Post in your existing thread. No need to create a new one.

Duplicate
https://www.sololearn.com/Discuss/3255101/?ref=app

Answer 4

Zoya

There is \n, \t

What about your above problem?

Answer 5

Assuming u don't especially need if else conditions to find out so

https://sololearn.com/compiler-playground/ckMT6fk1UqWu/?ref=app

Answer 6

Please explain i don't understand

Answer 7

#include <iostream>
using namespace std;

int main() {
int x,y,z;
cin>>x>>y>>z;
if(x>=y){
if(x>=z){
cout<<"largest number is "<<x;
//cout<<"largest number is "<< y;
}
}else{
if(y>=x){
if(y>=z){
cout<<"largest number is "<<y;
}
}
}
if(z>=x){
if(z>=y){
cout<<"largest number is "<< z;
}
}
return 0;
}

Answer 8

Is it right

Answer 9

Why we use /n
and
/t