Recursive call is None?

Question

Why is recursive call of this function None for x = 2?

def function(x):
if x == 1:
return x
else:
x -= 1
print(function(x))
function(x)
x = 2
print(function(x), x)

Output:
1
None 2

Answer 1

Oh, I just realized that return keyword is missing in front of recursive function call:
return function(x)

Answer 2

Jovica Spasic
you might want to change == to <= to prevent infinite recursion for x<1.

def function(x):
if x <= 1:
return 1
else:
x -= 1
print(function(x))
return function(x)

#test
for x in range(-5,5):
print(function(x), x)