+ 1

# Can someone please help explain the step process in this coding.

def f(x): if x == 0: return 0 return x + f(x - 1) print(f(3)) The ‘f(x’ in line 4 is confusing me. Because I’m not to sure if that puts it through the function again all over again.

23rd Sep 2021, 4:43 PM
Jenkins
2 ответов
+ 4
It's recurrence We are again calling the function but by decreasing the value of x by 1 Until and unless x doesn't becomes zero it will keep on adding the value of x and then return it . So the fxn will return 3+2+1 =6 but as x becomes Zero it returns 0 and then it returns 6 .
23rd Sep 2021, 4:58 PM
vardhan ray
+ 3
The function is a recursive function means return itself until the condition is not acceptable. In your code, the beginning value is 3 and the condition is 0, the function decreases the value one by one and returns itself until the value becomes 0. Running process: Beginning value: 3 Return value: 3+f(2), 2 is greater than 0, so continue Return value: 3+2+f(1), 1 is greater than 0, so continue Return value: 3+2+1+f(0), 0 equals to 0, so the function stops to return itself. I hope, it's clear enough. Happy coding!
23rd Sep 2021, 5:37 PM
mesarthim