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# Please help me! Read Description. 🙏🏻🙏🏻🥺🥺

#include<stdio.h> int main() { int a = 2, b = 3; a = a + b - (b = a); printf("%d %d", a, b); return 0; } Output: 3 2 Why output is 3 2?? According to priority, bracket should be solved first. Why (b = a) is not evaluated first? As it has brackets around it, increasing it's priority. So why it is not like this? >> a = a + b - (2) >> a = 2 + 2 - 2 (Cuz b is 2 now) >> a = 2. Why it is not like this? What's the meaning of bracket then? Priority should be given to brackets first? Please explain.

19th Feb 2021, 11:20 AM
Mahima Rajvir Singh
13 ответов
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Angelo , A. S. , Jayakrishna🇮🇳 , Mr.Imperfect , Théophile and Ярослав Вернигора(Yaroslav Vernigora) Thank you so much all of you. Now, I am clear about it. So grateful to have SoloLearn app! ✨😊
19th Feb 2021, 2:51 PM
Mahima Rajvir Singh
+ 4
Hello First of all, I recommend you to learn "operator priority" This link will help you. https://en.cppreference.com/w/cpp/language/operator_precedence And here are the examples. https://www.programiz.com/cpp-programming/operators-precedence-associativity
21st Feb 2021, 8:21 AM
Cem köylüoğlu
+ 3
You are confusing execution with evaluation a = a + b - (b=a) First evaluates the components (in an undefined order): a= 2 + 3 - (b=2) Than it executes (With parenthesis you change the order of execution)
19th Feb 2021, 11:53 AM
Angelo
+ 3
As Angelo tried to say, we don't care about the result : it is UNDEFINED BEHAVIOR, meaning that nobody can predict the result. As a general rule, we don't modify the value of a variable inside an expression, since it leads to undefined behaviors.
19th Feb 2021, 12:11 PM
Théophile
+ 2
Maybe it's better with an example: a= 2 * 3 + b Evaluation: a=2*3+3 Execution: a=6+3 a=9 a=2*(3+b) Evaluation: a=2*(3+3) Execution: a=2*6 a=12
19th Feb 2021, 11:59 AM
Angelo
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Hi! maybe it will help you to better understand the visualization of the code step by step. here on this site. true, I have never used it yet, and so I am not sure that it will work in your case, but still try it: http://pythontutor.com
19th Feb 2021, 12:01 PM
Yaroslav Vernigora
+ 2
Evaluation expressions is left to right for equaliry operator.. here a = a + b -(b=a) Here, before assigning b=a , first b is already gets replaced by its previous value 3. After that b value changed to a in stack so it is evaluated as a = 2+3-(2) = 3 So now a =3, b =2 but order of execution of expressions is compiler dependent in c/c++.
19th Feb 2021, 12:10 PM
Jayakrishna 🇮🇳
+ 1
No, although there are some rules (that change between versions of c/c++), the order of evaluation is undefined
19th Feb 2021, 11:34 AM
Angelo
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a=a+b-(b=a) => a=2+3-(b=2) => a=5-2 => a=3 Than print 3 2
20th Feb 2021, 6:41 PM
Jai Prakash Patel
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According to first of all solve bracket then solve next a=a+b-(b=a) a=2+3-2 a=3 Then print 3 2 Because you are change value before print.
5th Mar 2021, 11:23 AM
Jai Prakash Patel
0
Angelo But why output is coming 3 2?
19th Feb 2021, 11:35 AM
Mahima Rajvir Singh
0
A. S. If 'b' becomes 2 then why first 'b' in the expression is taken as 3? Why not a=2+2-2 ??
19th Feb 2021, 11:41 AM
Mahima Rajvir Singh
- 1
C plus plus class I am new student
22nd Feb 2021, 6:07 AM
Sham Sham