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# But isnt num 7 and num == 7 shouldnt the answr be 7

4 ответов

+ 6

no

+ 2

wut

+ 1

The answer is since the second condition
if num < 5:
print("5")
fails , it would ideally go to else part of it. Since here we do not have a else condition, it comes out of loop. Hence third if is not executed.

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Hello! here is my explanation:
num = 7 <---This is the given value
*if num > 3: <----This is the 1st condition, if it´s not satisfied then the program goes to condition #2
print("3")
*if num < 5: <---- This is the second condition,if not satisfied goes to condition #3
print("5")
*if num ==7: <----This is the third and final condition.
print("7")
As we can note, the number given is 7 and 7==7 right? Mathematically it is true, but the "If" condition in the program evaluates the input in a logical way as I explained above: Value given, if condition #1 is true the program ends, if not then evaluates condition #2, and so on. Because the first condition is TRUE (7 is greater than 3) then the program ends and the result is 3 because that is the instruction( print("3")).
*P.D. In fact we will never get to the final condition (7==7) because the program would end immediately in the first condition.
*P.D. Sorry if I do not explain myself clearly.