How does "a" become 4, or it's mistake? I thought it should be 2 O.o

Question

int x(int &a,int &b){
a = 3;
b = 4;
return a+b;
}
int main(){
int a = 2;
int b = 7;
int c = x(a,a);
cout << a << b << c;
}
RESULT: 478

Answer 1

I'd say you need to return a integer in the x method or make it an void.

Answer 2

Yes I get it, tnx :)

Answer 3

yes, i forgot to write it, but it's not the problem

Answer 4

ok using int &b or int &a in int x(...) you create an int with the same address as a in int main(), so a and b in int x(...) and the other a, too, are the same, but the last assignment is b = 4, which sets all three ints to the value 4
I hope you get what I mean