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Need help with the gold purity Boolean logic problem

I'm running this code and it's showing errors on test 5 purity = float(input()) if purity >= 75.0 and purity < 83.3: print ("18K") if purity >= 83.3 and purity < 91.7: print ("20K") if purity >= 91.7 and purity < 99.9: print ("22K") if purity >= 99: print ("24K") Any help would be appreciated šŸ™‚

6th Aug 2021, 1:18 PM
Tophyy
Tophyy - avatar
6 Respostas
+ 5
Try: purity = float(input()) if purity >= 75.0 and purity < 83.3: print ("18K") elif purity >= 83.3 and purity < 91.7: print ("20K") elif purity >= 91.7 and purity < 99.9: print ("22K") elif purity >= 99.9: print ("24K")
6th Aug 2021, 1:28 PM
Aleksei Radchenkov
Aleksei Radchenkov - avatar
+ 1
Could you post the task here?
6th Aug 2021, 1:21 PM
Aleksei Radchenkov
Aleksei Radchenkov - avatar
+ 1
Thank you that worked. What was I doing wrong then šŸ˜…
6th Aug 2021, 1:31 PM
Tophyy
Tophyy - avatar
+ 1
1. use elif so statements are only considered if original if is not the case. 2. You wrote >= 99 instead of 99.9 in the last statement
6th Aug 2021, 1:32 PM
Aleksei Radchenkov
Aleksei Radchenkov - avatar
+ 1
Oh thank you I didn't see the 99.9 part and I'll remember to use elif also thanks.
6th Aug 2021, 1:34 PM
Tophyy
Tophyy - avatar
- 1
Now that we know how to combine multiple conditions, letā€™s improve our gold purity checker program and output the corresponding purity level in Karats! Here is the purity chart weā€™ll be using: 24K ā€“ 99.9% 22K ā€“ 91.7% 20K ā€“ 83.3% 18K ā€“ 75.0% If the percentage is between 75 and 83.3, the gold is considered to be 18K. If it's between 83.3 and 91.7 - then itā€™s 20K, and so on. Given the percentage as input, output the corresponding Karat value, including the letter K. Sample Input: 92.4 Sample Output: 22K
6th Aug 2021, 1:22 PM
Tophyy
Tophyy - avatar