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Binary equivalent
Can anyone tell how the code works in converting decimal no. to binary void Binary(int n) {if(n>1) (n/2); cout<<n%2; }
5 Respostas
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~ swim ~
Ok. I thought he using while loop.
For recursion no need but by loop I mentioned. Because of just said binary process without considering code as it is incomplete... 
OK. I edit as an alternative way.. Thank you..
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TY GUYS...my tutor said that the reminders are stored on stack...and it was a little bit difficult to understand...but the way swim told make sense...TY
0
[ Edit: 
if you know binary convertion, and looking for recursive explanation only, then see @swim explanation.. ] 
For ex: 8
8%2=0,  8/2=4
4%2=0,  4/2=2
2%2=0,  2/2=1
1%2=1,  1/2=0 stops, 
So 01000,   Take reminders in reverse... 
1000 is 8's binary representation..
Your code has some flaws..
It should store reminders and print in reverse..
Edit:
Without recursion, code may look like...
void Binary(int n)
{
int a[20], i=0;
while(n>0){
a[i++]=n%2;
n=n/2;
}
for(int j=i-1; j>=0 ; j--) 
cout<<a[j];



