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In JavaScript? Why Str and Int confusion?
When I try document.write(ā2ā + ā2ā); It outputs 4 Why?? Same... var int = 3; var str = āhiyaā; document.write(int * str); Why doesnāt it output hiyahiyahiya But instead gives me NaN?
4 Respostas
+ 2
i don't really now this, but it seems that js converts the strings to int, if you multiply them, and returns them as int.
When the result can't be an int, it will become NaN
tests:
document.write(2*3); //6
document.write("\n");
document.write(2*"3"); //6
document.write("\n");
document.write("2"*3); //6
document.write("\n");
document.write("2"*"3"); //6
document.write("\n");
document.write("hi"*3); //NaN
document.write("\n");
document.write("hi"*"3"); //NaN
document.write("\n");
document.write(3*"hi"); //NaN
document.write("\n");
document.write("3"*"hi"); //NaN
document.write("\n");
+ 1
sorry I made a mistake in my first bit.
document.write(ā2ā * ā3ā);
outputs 6 and I dont understand why
+ 1
why is int an invalid variable? is int forbidden?
see this code as a similar example:
var test1 = 3;
var test2 = "hiya";
document.write(test1 * test2);
//output NaN
0
://First of all
document.write("2"+"2") output is not "4", it is 22 because they are between quotes, which makes them string
://Second var int is invalid variable, you don't need describe in int, str for numbers and strings