Need help in this.

Question

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
int a = 6, sum = 0, n1 = 0, n2 = 0, n3 = 0, n4 = 0, n5 = 0;
int i = 1;
while (i <= 5)
{
if (a%i == 0)
{
n1 = i;
}
else if (a%i == 0)
{
n2 = i;
}
else if (a%i == 0)
{
n3 = i;
}
else if (a%i == 0)
{
n4 = i;
}
else if (a%i == 0)
{
n5 = i;
}
else
{
cout << "Invalid" << endl;
}
i++;
}
sum = n1 + n2 + n3 + n4 + n5;
cout << sum << " is perfect number" << endl;
_getch();
return 0;
}

Answer 1

Determine a perfect number is much easier.

Look:

#include <iostream>
using namespace std;
int main()
{
int n;
cin >> n;

int i = 1;
int sum = 0;

while (i < n) {
if (n % i == 0) {
sum = sum + i;
}
i++;
}

if (n == sum)
cout << n << " is perfect number." << endl;
else
cout << n << " is not perfect number." << endl;
}