what is the error in this code and what is it's solution? (python code)

Question

Following code has used iter method and next method inside class, in order to print no upto 5 from 1.
class myclass:
def __iter__(self):
self.x=1

def __next__(self):
y=self.x
self.x+=1
return y

obj=myclass()
it=iter(obj)
print(next(it))
print(next(it))
print(next(it))
print(next(it))
print(next(it))

The error is actually in line: it=iter(obj), it is saying that obj is not iterable type

Answer 1

here it is, you need a __iter__
https://code.sololearn.com/c50o5V4Q68et

Answer 2

__iter__ is used for things like this:
for a in cls:
print(a)
or
list(cls)

class myclass:
def __init__(self):
self.x = 0
def __next__(self):
self.x+=1
return self.x

Answer 3

The error is actually in line: it=iter(obj), it is saying that obj is not iterable type

Answer 4

oh, because it's really not iterable😂
maybe try 'yield y' at the last line of next🤔

Answer 5

isn't helping, a new error appears now

Answer 6

I'm trying it🤔

Answer 7

thanks, i got this!

Answer 8

error appeared due to the fact that iter method should return iterating object whenever used in a class.

Answer 9

return self or return obj in iter method will solve this error. thanks everyone!

Answer 10

it.next()