Diference between arr[2] and arr[i/2]

Question

i have this code:

var arr = [4, 2, 10, 5];

for (var i =0; i<arr.length;i++){
arr[i] *= i;
}
alert(arr[i/2]);

the output is 20, If it was alert(arr[2]); is 20 too. why?

sorry, my english is very poor.

Answer 1

Felipe Medeiros No problem 😊
inside the for loop
when i=0 arr[0] becomes 0
ie 4*0=0
when i=1 arr[1] becomes 2
when i=2 arr[2] becomes 20
when i=3 arr[3] becomes 15
when i=4 it fails to satisfy the given condition. So now i=4
So when alert arr[i/2] it is actually arr[2] (4/2=2) so the output is 20

Answer 2

because array.length is 4. after the loop i=array.length=4 and therefore i/2=4/2=2 so alert(array[i/2]) is the same as alert(array[2]) for this array