+ 1

Another problem

int a,b,c,d, e=11; a=b=c=d=0; do{ e = e+1; a = a+1; if(a>=2) b = b+1; if(b>=2) c = c+1; if(c>=2) d = d+1; if((a&&b)&&(c&&d)){ printf(" %d",e);break; } }while(1); //end didn't understand the last if statement, if anyone can please explain.

23rd Mar 2018, 8:00 AM
Akib
Akib - avatar
5 Respostas
+ 17
logical & operator returns true for any values other than 0 for eg.:- 1&&0 = 0 (false) 0&&0 = 0 (false) 1&&1 = 1 ( true) 2&&3 = 1 (true) 5&&7 = 1 (true) n1&&n2 = 1 (true) ; where. n1,n2 ≠ 0 https://www.sololearn.com/learn/CPlusPlus/1619/?ref=app
23rd Mar 2018, 11:46 AM
🌛DT🌜
🌛DT🌜 - avatar
+ 16
yes sorry it will output 15 1st time the condition of last if will be false then 2nd time it will be true it will break after printing 15 did u got the idea about last if statement
23rd Mar 2018, 8:41 AM
🌛DT🌜
🌛DT🌜 - avatar
+ 15
a = 0 + 1 = 1 b = c = d = 0 since all if has false condition therefore in last if if ((1&&0)&&(0&&0)) { printf("something"); break; } condition false nothing happens... because of while(1) results in infinite loop
23rd Mar 2018, 8:23 AM
🌛DT🌜
🌛DT🌜 - avatar
+ 1
this outputs 15. not infinite loop
23rd Mar 2018, 8:38 AM
Akib
Akib - avatar
+ 1
sorry i don't understand how if(1&&0) works. can you please explain?
23rd Mar 2018, 9:33 AM
Akib
Akib - avatar