Novo curso! Todo programador deveria aprender IA generativa!
Experimente uma aula grƔtis+ 27
Tiny Math Challenge
https://code.sololearn.com/Wf5vHTYEoQ3Q/?ref=app I wrote the answer in the code (don't lose attention, guysš)
16 Respostas
+ 26
7 & 11&5&3 are also factors of 1155 ...
//0,2,4,8,6 comes as last digit 2^n , on substracting 1... we get 9,1,3,7,5 as last digit , still some possibility of getting divisible bcz of 5 as last digit also possible & now what ?
//there are numbers possible which have last digit as 5 & div. by 7,11&3 ...
//i am also confused š
+ 24
take log āŗš
use log2=.3010 & log as .4771
log y = 2^2007+ 3^2008 -2009 . log2 //will see 1 later
y=10^((2^2007+3^2008-2009).log2)
=10^(10^(2007.log2)+10^(2008.log3)-2009) . log2
then check whether y-1 is div by 1155 or not
+ 20
It's much better, Gauravššš continue, please, extend and COMPLETE your answer
+ 19
Without logarithms...please
+ 19
Look at the last Gaurav's answer, Jay. He began correctly...
+ 19
Hint:
Answer - yes. Why?..
+ 18
@Jacob, it's not about code, it's challenge (aka, question) because I can't make pretty formating presentation of it here without html + cssš
+ 17
Nope(not very correct) @Gaurav, don't calculate, pleaseš
Multiplicity and divisibility will help you, dearāŗ
+ 16
@jay, just try to effort to thinkingš It's not so hard, believe me, mateš
+ 16
@LunarCoffee
Nope(not very correct) @Gaurav, don't calculate, pleaseš
Multiplicity and divisibility will help you, dearāŗ
+ 16
@Learnsolo, no, without calculator, please!āŗ
+ 8
Count me out, math hates me :)
+ 7
It's 12:17am... I math better in the morning. I will check it out/try though :)
+ 7
Can you use a calculator? š
I need calculator to complete š
+ 1
I'm in Grade 8 (Canada) and have no idea how to solve this without just... calculating it.
0
I just found this challenge and its pretty late here I'll try it tomorrow.
Even though its already answered it will be a good exercise.