>> and %*d meaning in C

Question

#include <stdio.h>

int main() {
int i=2048;
while(i){
printf ("Sololearn\n");
i>>=1;
}
return 0;
}
This code prints 'Sololearn ' 12 times. Can someone tell me why this happens and what does >> do in C?
#include <stdio.h>

int main() {
int x=4;
printf ("%*d",x,42);
return 0;
}
Another question is that why this code outputs 42 instead of 4 and what is the use of %*d in C?

Answer 1

>> is bitwise right shift, there is also a left shift and you can see here what exactly does
https://www.geeksforgeeks.org/left-shift-right-shift-operators-c-cpp/

about the "%*d" you can see here what it does
https://www.quora.com/What-does-printf-*d-*d-a-b-mean-What-about-the-format-specifier

Answer 2

">>" - This is a bitwise operator that shifts a binary number by a certain value to the right, that is, 4>>1 equals 2, (essentially divides the number in half):

4 2
100>>1 equals 010
100>>2 equals 001

In the second case, the indentation increases four times minus the number of characters of the printed value.
42 consists of two characters meaning 4-2 equals 2 indentations.