can someone solve this and explain in depth?

Question

Write a program that takes a number as input and
- returns its double, if the number is even
- returns its triple, if the number is odd
- returns 0, if number is 0

I can't solve it yet :((

edit: I solved it a couple minutes ago but thank you everyone! I expected that I was gonna get called dumb cause I couldn't solve something simple, thanks a lot everyone!

Answer 1

Frankly speaking I suck at python but just telling you the logic,

num = int(input())
Take an input integer

Than take a if statement,

if(num%2==0)
print(num * 2)

Since it's written that if the number is even ( numbers which have remainder 0) it returns the double of the input number.
return num

Than for the second condition, take another if statement,
if(num%2==1)
print (num * 3)

Since it's written that if the number is odd ( numbers which have remainder 1) it returns the triple of the input number.
return num

Last condition states that if the input no. is 0

if(num == 0)
print("0")

There are many other methods to solve this but I think this might be easy (according to me)
Hope it clears
I really suck at python 😅

Answer 2

Joshua Quitoy here is the code simplistically
# input a number
x = int(input())
# double it
y = (x*x)
print(y)

# check rather even or drop through for odd
if ( y%2 == 0):
print(y*x)
else:
print(0)

input a number // x = int(input())
- returns its double ( x*x )
if the number is even ( x*x)%2 == 0
- returns its triple, ( x * x * x )
if the number is odd
- returns 0, if number is 0

Answer 3

Why dont people realize that 0*2 = 0?

Answer 4

https://code.sololearn.com/cgxH0kL0u3k4/?ref=app

Maybe this can help

Answer 5

https://code.sololearn.com/cY6RyHzNFUgR/?ref=app

Answer 6

That is rather smart Zachiah sawyer 👌👌

One-liner-ish solution based on Sawyers'

x = int(input())
print(x*2 if x%2==0 else x*3)

Answer 7

1 Use modulus fn to get even or odd
2 Return 0 if zero 😶

Answer 8

x = int(input())

if x % 2 == 0:
print(x*2)

else:
print(x*3)