+ 4

# how the answer will be 5 can anyone explain?

#include <stdio.h> int main() { int x=1; while(x++<=1) while(x++<=2); printf("%d",x); return 0; }

20th Aug 2019, 3:07 PM
Mr. Bhattg
3 Réponses
+ 5
Why semicolon 👉🏻 while(x++<=2); ?? Try it without semicolon you will get output 3
22nd Aug 2019, 8:41 AM
Ayushi Gujarati
+ 5
https://code.sololearn.com/cmxq29mPRD0W/?ref=app /* line7: x=1 line8: while(x++<=1) //true as 1<=1 function of x++(post increment operator) first use then increase so value of x=1 will be used in this loop then increment will take place now x=2 line9: while(x++<=2); //true as 2<=2 again post increment will work so now x=3 now it will again check while(x++<=2); //false as 3<=2 is false but again post increment will work so now x=4 so now compiler will jump to line8 as statement in line9 failed line8: while(x++<=1) //false as 4<=1 is false again post increment will work so x=5 now compiler will jump to line11 line11: printf("&d",x); // 5 so 5 is your output hope you understood... comment back for any other query */
1st Sep 2019, 11:22 PM
Mayank Matwa
+ 2
When we enter the 1st loop the x will become 2 after the test and it will test on the second loop 2==2 so it's true and it's gonna increment then gonna check again the second loop but this time it's gonna be false but even though it's gonna increment now x=4 test the wrapping loop and increment x=5 and done, the problem was in the way this increment works inside loops even if it's not true it is going to increment whether the test true or false
21st Aug 2019, 3:05 AM
assellalou
Aujourd'hui en vedette
Python