Can someone explain this ?

Question

void f(int m[5]){
for (int i=0;i<3;i++)
m[i]*=2;
m++;
}
int main()
{
int a[5]={1,1,1,1,1};
f(a);
for(int i=0;i<5;i++)
cout<<a[i];
} // Output 22211

Answer 1

Let's start from the top. We have a function which accepts an array of 5 elements as arguments.

What it does is that it multiplies the first 3 elements by 2.

In the main method we call that function with the array 'a'.

So the function modifies that array which essentially multiply the first 3 elements by 2.

An at last we print each value of the resulted array and it prints 22211

Answer 2

I think the m++ is unnecessary because the result is the same.