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n = int(input())
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4 Respuestas
Write a program in C++, if n =3 it will print 333 313 323 333, if n= 4 it will print 4444 4414 4424 4434 4444
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I need to find sum of series 1/2+1/4+1/8+..
n= int(raw_input("enter the limit")
s=0
i=2
while(i<=n):
x=float(1\i)
s=s+x
i=i+2
print s
is this the correct program??
1 Voto
2 Respuestas
double arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
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