Sesiones de PyR

Тонкости Angular и Node
angularangular.jsjslibnodenode.jsбибллиотекитонкости
-1 Voto
1 Respuesta
1st Apr 2018, 8:46 PM
Костюков Александр
Костюков Александр - avatar
En tendencia hoy
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Conducción de calor o Q=−kAdTdxQ = -k A \frac{dT}{dx}Q=−kAdxdT o Pared 2 m², espesor 0.1 m, k = 50 W/m°C, ΔT = 30°C → Q ≈ 30,0
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