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How to write a program to find a number is even or odd. Print "even" or "odd" on screen conditions : don't use / % conditional statements if else switch and loops for while & do while
8 Respuestas
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std::string array [2] = { "Even", "Odd" };
int a = 10;
cout <<array [ a & 1];
It's solvable and enjoy
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are you sure not to use if-else?
without if-else...the question seems unsolvable
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it is solvable without if-else
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No, any conditional statements are not needed
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my mind's not working....anyone got some idea???
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I don't think its possible
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If it's an integral number you have to check if the last bit is set. If so, it's uneven. Go from there.
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no idea , may be its unsolvable