How this output has came?

Question

#include <stdio.h>
int main() {
float a;
a = 0.7;
if(0.7>a) {
printf("Hi");
}else{
printf("Hello");
}
return 0;
-----------------------------------------
OUTPUT
Hi

Answer 1

G'day Ritwick Raj Makhal it is a binary to decimal rounding error.

Add this to your code and see what the value of a becomes:

printf("%.16f",a);

https://code.sololearn.com/c8Joyu2AI8yi/?ref=app

Answer 2

It happens because the comparison took two floating point values of different precision as operands. The 0.7 literal is a `double` while <a> was a `float`.

The difference may be noticeable when printing the two values with enough decimal points specified, as demonstrated by HungryTradie above ...

You can compare <a> with a `float` literal (rather than `double` literal) by appending 'f' to the literal, which specifies the literal to be a `float` rather than a `double`.

if( 0.7f > a ) // <- notice the 'f' suffix

But this far I have learned that floating point comparison just can't be as solid as integer comparison : )