0
what is output of code and how?
int c=0 if(c) printf("%d",c=0); else printf("%d",c=1); printf("%d\n",c);
2 Respuestas
+ 2
Well it will produce error correct code is \/
#include <stdio.h>
int main() {
int c=0;
if(c){
printf("%d",c=0);
}
else{
printf("%d",c=1);
printf("%d\n",c);
}
return 0;
}
you are suggested to go through the course
https://www.sololearn.com/Course/C/?ref=app
+ 1
After correcting the missing #include and missing ; the output would be:
11
Here is why. See comments.
#include <stdio.h>
int main() {
int c=0; // initial value is 0
if(c) // 0 is false. Skip to else.
printf("%d",c=0);
else
printf("%d",c=1); // assign 1 to c, print it
printf("%d\n",c); // print c again, 1
return 0;
}