+ 2

Reverse string - problem solving

https://code.sololearn.com/c8te5Dzc0SJP Please view this. I am facing a lot of issue solving. I want to give a string as input and get its reversed value as output.

17th Sep 2021, 3:58 AM
Ojas Kanotra
Ojas Kanotra - avatar
10 Respuestas
+ 5
U did mistakes in the for loop condition, also recreating same string inside the loop multiple times. Also always remember that index starts from 0. So lets say the length of your input is 5 but actually the characters will be present only from 0 to 4. Here I have corrected your code https://code.sololearn.com/cGcL48Rydb10/?ref=app
17th Sep 2021, 4:26 AM
Niththish
Niththish - avatar
+ 5
A few issues. 1. Line 6 subtract 1 from the length to start the loop at the last index of the input string. 2. Move the declaration of the String reverse outside of and before the loop. Set its initial value to an empty String "". 3. Fix your for loops condition so that the loop goes as long as y is greater than or equal to 0. 4. Remove 'String' from line 9, inside the loop, so as not to re-declare reverse inside the loop.
17th Sep 2021, 4:29 AM
ChaoticDawg
ChaoticDawg - avatar
+ 5
import java.util.Scanner; public class Program { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String input = scanner.nextLine(); int x = input.length() - 1; String reverse = ""; for(int y=x; y >= 0; y--){ reverse += input.charAt(y); } System.out.println(reverse); } }
17th Sep 2021, 4:35 AM
Erlénio.RS
Erlénio.RS - avatar
+ 3
1st error: the value of the variable x is greater than the number of characters. Solucionar: Subtracts x by by 1 or (input.length - 1). second: your array will not execute with this condition. Solution: Replace with for(int y = x; y >= 0; y++). Third: the reverse variable is only visible for the [for block]. Solution: declare a out of scope for and initialize it with an empty string.
17th Sep 2021, 4:34 AM
Erlénio.RS
Erlénio.RS - avatar
+ 2
Thanks everyone. It helped a lot.
17th Sep 2021, 10:10 AM
Ojas Kanotra
Ojas Kanotra - avatar
+ 1
Do not define new string. Try replacing the first half of the string with the second half. if the length was odd you don't have to change the middle character. This way is faster.
17th Sep 2021, 7:25 AM
Mani_K_A
0
Reverse variable must be string not integer
17th Sep 2021, 12:43 PM
ūüĆÄ Shail Murtaza ōīōĻŘĆŔĄ ŔÖōĪō™ō∂ŘĆŔį
ūüĆÄ Shail Murtaza ōīōĻŘĆŔĄ ŔÖōĪō™ō∂ŘĆŔį - avatar
- 1
You have done on mistake, i.e. data type Instead of 'int' use 'String' in reverse variable Hope you like it https://code.sololearn.com/c7U6o8HuE1VK/?ref=app
17th Sep 2021, 3:56 PM
Kittu
Kittu - avatar
- 1
import java.util.Scanner; public class Program { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String input = scanner.nextLine(); int x = input.length(); String reverse = ""; for(int y=x-1; y >= 0; y--) /*1. x-1 since its reference to index -2. y>=0 mean loop will run till the time y is greater than or equal to zero*/ reverse += input.charAt(y); System.out.println(reverse); }}
19th Sep 2021, 3:19 AM
pulkit goel
- 1
public class lesson18arraystring { public static void main(String[] args) { Scanner read = new Scanner(System.in); String conver = read.nextLine(); char[] cha = new char[(conver.length())]; int length = conver.length() - 1; for (int i = 0; i <= length; length--) { cha[length] = conver.charAt(length); System.out.println(cha[length]); } } } //first creating same size array char //second convert string turns to char array list //display array list backwards
21st Sep 2021, 7:40 AM
jiaqi chen
jiaqi chen - avatar