How to find even digits out of a given number? eg:2475

Answer 1

First take n as input
Then
while(n!=0)
{
d=n%10;
if(d%2==0)
System.out.println(d);
n=n/10;}
This will print the even nos of the no entered

Answer 2

If x % 2 is 0, it is even.

Answer 3

Thank you...
Is there any other way?

Answer 4

Thanks ☺

Answer 5

uhm, I’m pretty tired, but if you’re looking to find even digits in a whole number, all that comes to mind is variable manipulation haha:

String num = "2475";
for(char c : num.toCharArray()){
int digit = Integer.parseInt(Character.toString(c));

if(digit % 2 == 0)
System.out.println(digit);
}

Answer 6

int[] nums = {2,4,7,5};
for(int num : nums) {
if(num % 2 == 0)
System.out.println(num);
}