can someone explain this ?

Question

int sum(int a=2,int b=9){
return a+b;
}

int main()
{
int(*psum)(int,int);
psum=∑

cout<<*psum; //output1
return 0;
}

Answer 1

You have a function pointer that points to a function which takes 2 ints and returns one, you assign sum to it and print the function without calling it, so you get true/1.

Answer 2

Also the reason why it prints 1 is because cout doesn't have an overload for a int(*)(int,int) function pointer.
The next available option is a bool which just converts any address to a 1.

You'd need to overload the specific function pointer yourself for std::ostream operator<< if you want it to print it's actual address.