Answer 1

You can, though I can't see a proper use for it. I wouldn't recommend it either.

int *p =(int*) 0x29fee8

Casting pointer to int and back:
http://code.sololearn.com/c5tBxVCz7xKD

You need to dereference a pointer (with *) to access to the value pointed.

int i = 42;
int *p = &i;
cout << *p << endl; //dereferences p and prints 42