How to have this code return None?

Question

How to make the following code return none if the new_list remains empty?

def largest_odd_times(L):
""" Assumes L is a non-empty list of ints
Returns the largest element of L that occurs an odd number
of times in L. If no such element exists, returns None """
new_list = []
if True:
for elm in L:
if L.count(elm)%2!=0:
new_list.append(elm)
elif len(new_list) == 0:
return None
else:
return max(new_list)

print(largest_odd_times([3,9,5,3,5,3]))

In case i call this function with list [2,2], it should return None instead of a ValueError.

I refined this code to this:
new_list = []
for elm in L:
if L.count(elm)%2!=0:
new_list.append(elm)
else:
continue
return max(new_list)

Answer 1

add instead of the return
if not new_list:
return None
return max(new_list)

(Edited)

Answer 2

Sorry for the mistake ^^

Answer 3

This Works:
new_list = []
for elm in L:
if L.count(elm)%2!=0:
new_list.append(elm)
else:
continue
if not new_list:
return None
return max(new_list)

Thank You