What is the output this code?

Question

str=[1,2,3]
if 0 and 1:
print (str[2])
elif 1 or 0:
str = str[::-1]
print(str[2])

This answer is 3. Why?

Answer 1

Paste this code in an IDE and you'll find the answer is 1. This is because the if statement is false, and the elif statement is true. The string is reversed, and the value at index 2 is now 1. (The new string is 3,2,1).

Answer 2

I got it.

If -1 of line 5 changes to 1, this answer is 3, right?

Answer 3

Correct Johnny, because it'll loop through str forwards, and str will still be [1,2,3], so index 2 will yield 3.

Answer 4

Thank you for your comments!
I understand all very well.