What is the Output and how explain?

Question

public class Program
{
public static void main(String[] args) {

int x=1 ,y=1, z=0;
if(!(x++>1 && y++>1))

{
z=x+y;
}
System.out.println(z);
}
}

Answer 1

if(!(x++>1 && y++>1))
Here x++ its Post increment
*So first the x is compared to 1 i.e. x>1 is false
then x values is incremented So Now x=2.

*Since we are using && operator since one condition is false it will not check the other condition since it will be false anyways. So y=1.

*!() Not operator makes that condition true .

so the inside code gets executed

z=x+y;
z=2+1;

Output : 3

Answer 2

3
x++>1 is false (1=1). x incremented afterwards and equals 2 then (afterwards, in any next lines, evaluations...)
Left part of && is false so right part is not evaluated (no need for it) and y is still equals 1. Condition of "if" is true (because !(false) so = true) and z is equal 2 + 1 so it's 3.