Answer 1

I would try a dictionary/hashmap.

key = letter
value = counter

While you loop over the string you check if the letter is in your dictionary/hashmap: if yes: increment counter, if no: create new key

The first letter where counter = 1 is your first letter that is not repeated.

Answer 2

Arvind ,

it would be helpful if you can do a sample input and output.

please also mention if you mean consecutive repetition or repetition in general.

Answer 3

The count should be 1 if it is not repeated.

Answer 4

You can do this by using nested for loops and can be done using hashmaps.

Answer 5

please type your project link so we can help you! :)