0

# << means ?

2 Answers

0

The left-shift operator (<<) shifts its first operand left by the number of bits specified by its second operand. The type of the second operand must be an int or a type that has a predefined implicit numeric conversion to int.
EXAMPLE:
class MainClass11
{
static void Main()
{
int i = 1;
long lg = 1;
// Shift i one bit to the left. The result is 2.
Console.WriteLine("0x{0:x}", i << 1);
// In binary, 33 is 100001. Because the value of the five low-order
// bits is 1, the result of the shift is again 2.
Console.WriteLine("0x{0:x}", i << 33);
// Because the type of lg is long, the shift is the value of the six
// low-order bits. In this example, the shift is 33, and the value of
// lg is shifted 33 bits to the left.
// In binary: 10 0000 0000 0000 0000 0000 0000 0000 0000
// In hexadecimal: 2 0 0 0 0 0 0 0 0
Console.WriteLine("0x{0:x}", lg << 33);
}
}
/*
Output:
0x2
0x2
0x200000000
*/

0

Thanku