+ 4
# your code goes here
a=1000000*(2**30)
b=0.01*(2**30)
mi=a
if(a>b):
mi=b
print(mi)
+ 6
# your code goes here
z=1000000*(2**30)
y=0.01*(2**30)
money=z
money=y
print(money)
+ 3
a=1000000
b= 0.01*(2**30)
if a>b :
print(a)
else :
print(b)
+ 1
Hi! Please, show us your code attempt! Thx!
+ 1
1. what do the numbers 50 mean in your code?
2. how is the exponentiation operation performed in python?
3. what is del x operation?
+ 1
First of all, to clarify: the 1000000 isn't being multiplied. You're given to choose either 1 MLN or 0.01 cents to be multiplied daily to an amount of 0.01*(2**30).
So, your code, as I understand, should be as follows:
#your code
a=1000000
b=0.01*(2**30)
c=a
If (a>b):
c=b
print (c)
0
yes, that's right, repeat the python lesson of exponentiation. this will greatly facilitate your task
0
#your code goes here
x=1000000*(2**30)
y=0.01*(2**30)
ca=x
ca=y
print(ca)
0
You are the best, thank you
0
where does the 2 come into play?
0
Its very basic , dont confuse your self with some long answers here.
The answer is ;
print(0.01*(2**30))
GL
0
can anyone explain to me how is 0.01*(2**30), doubled everyday for 30 days ?
0
0.01 * 2 and so repeated 30 times
0
tha answer
geometric sequence
sum=V0+V1+......Vn=V0*((2**30)-1/2-1)
sum=0.01*((2**30)-1)
print(0.01*((2**30)-1))
- 1
a=1000000*(2**30)
b=0.01*(2**30)
mi=a
if(a>b):
mi=b
print(mi)



