Answer 1

Because of Double.NaN (literally: “Not a Number”).

This code:

final double d1 = Double.NaN; final double d2 = Double.NaN; System.out.println(d1 == d2);

will print false.

The most accurate way to tell whether two double values are equal to one another is to use Double.compare() and test against 0, as in:

System.out.println(Double.compare(d1, d2) == 0);

Answer 2

Intresting, I also didn't know that.