Can you please explain the output of this code?

Question

def fun1(a):
x = []
for i in range(a):
if(i%2 == 0):
x.append("+"*i)
return x
print(len(func1(6)))

Answer is 3

Answer 1

For the numbers 0, 2 and 4, a string is appended to the list.

['', '++', '++++']

There are three strings in that list, so len is 3.

Answer 2

for i in range 6
i%2==0//0%2==0 ,true
x.append("+"*0)//add "+" in zero time means x[]=[""]
1%2==0// false
2%2==0//true
x.append("+"*2)//add "+" in two time means x[]=["","++"]
3%2==0//false
4%2==0//true
x.append("+"*4)//add "+" in four time means x[]=["","++","++++"]
5%2==0//false and exit the loop
length(x)=3

Answer 3

in the function there is

for i in range(a):
if (i%2==0) :
x.append("+"*i)

To put it simply, it says that for every even number i ... Add "+" * i in the list x

Here a == 6

In range(6)

there are 3 even numbers

0, 2 and 4 (6 is not included)

So the list will be

x = [ "", "++", "++++" ]

There are 3 elements in list

return x will return this list

so len(func1(6))
Will give 3 as a result