Can you please explain the output of this code?

Question

def fun(a):
x = a**2
y = 0
while x >1:
x = x -1
y += 2
return y
print(fun(1) + fun(2))

Answer is 6

Answer 1

Here fun(1) will be 0 because x = 1**2 = 1 is not greater than 1.

And fun(2) will be 6 because x = 2**2 = 4 which is greater than 1. So loop will play untill x > 1 is true and 2 will be add in y everytime.

for fun(2):

x = 2**2 = 4;

while 4 > 1:
x = 4 - 1
y = 0 + 2

next time x will be 3 so

while 3 > 1:
x = 3 - 1
y = 2 + 2

again

while 2 > 1:
x = 2 - 1
y = 4 + 2

next time condition will false because 1 is not greater than 1 so it will not go inside the loop and finally y will be 6

Answer 2

fun(1)=> returns 0, since x=1**2,y=0 x>1 false, returns y

fun(2) => returns 6, x=2**2=4, y=0 then
x>1 true x=x-1=4-1=3, y+=2=>y=2

3>1,true x=3-1=2, y+=2=>y=4

2>1 true, x=2-1=1,y+=2=>y=6

1>1 false,
returns y #now y=6
print(0+6)
6

Answer 3

~ swim ~ debugging is possible here at codeplay? Because recently I can not access my computer