Can you please explain the output of this code?

Question

arr = [1, 2, 3, 4, 3, 2, 1]
a = list(map(lambda x:x % 2 == 0,arr))
if a [3] == True:
print("c")
else
print("d")

Answer is c

Answer 1

What about a[3] and a[0] ?

Answer 2

a[0] = 1 = odd = "d"
a[1] = 2 = even = "c"
a[2] = 3 = odd = "d"
a[3] = 4 = even = "c"
a[4] = 3 = odd = "d"
...
etc.

Answer 3

the 'map' maps each element in the list 'arr' to a co-domain defined on the function 'lambda x:x%2==2' that tests for even number.
Since the index 3 on the list 'arr' is even,
Where
a[0] is 1, odd
a[1] is 2, even
a[2] is 3, odd
a[3] is 4, even
the boolean tested true. Therefore, the string 'c' is printed

Answer 4

The list a contains True and False values. Since you mapped arr with lambda x: x%2 == 0, it returns True when a value of arr is an even number and False if not

arr[3] is an even number, so it prints "c"

arr[0] however is an odd number, so it prints "d"