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Question

#include <bits/stdc++.h>
using namespace std;
int main() {
int n,m,g,j,a;
cin>>n>>m>>g;
if (g>=m)
{
cout<<-1;
}
else
{
j=m-g;
n-=g;
if (n%j==0)
{
a=n/j;
cout<<a;
}
else
{
a=n/j+1;
cout<<a;
}
}
return 0;
}
What is missing from my code to accomplish this:
100 1
100
100

Another case would be this
80. 1
90
100
If I compile it, it gives me: - 1

Answer 1

The problem is this: A snail climbs every day M centimeters along a wall that measures N centimeters. At nightfall, the snail falls asleep and slips G centimeters. You must create a program that tells you how many days the snail will take to climb the wall.

Entry

N - the length of the wall

M- the number of centimeters the snail climbs each day

G - the number of centimeters the snail slips during the night

Departure

The number of days the snail takes to climb to the upper edge of the wall.

NOTE: in case the snail cannot reach the edge you must print -1

Answer 2

Israel Del Ángel Kindly copy paste your code on the code playground and then share that link in your post.

Answer 3

Israel Del Ángel Because in both the cases your g>=m is satisfied, so it prints -1.