Java code

Question

im confused about x++ and ++x and i need explanation of this code
https://code.sololearn.com/c3BFPNrretEU/?ref=app

Answer 1

Alright so...
X = 1
Y = 2
First loop prints
x++ + ++y;
x is still 1, y becomes 3 (pre-increment) = total 4.
After the loop ends, x becomes 2

2++ + ++3
x is still 2, y becomes 4 = total 6.
After this loop ends, x become 3

3++ + ++4
x is still 3, y becomes 5 = total 8
After this loop ends, x becomes 4

4 is bigger than 3 so loop ends with BREAK;

https://www.sololearn.com/learn/Java/2141/?ref=app

Answer 2

it is like
y=1+y; //++y before calculate
print( x+y );
x=x+1 // x++ after calculate

x=1 y=2 | x=1 ++y=3 | 1+3 = 4 | x++=2 y=3
x=2 y=3 | x=2 ++y=4 | 2+4 = 6 | x++=3 y=4
x=3 y=4 | x=3 ++y=5 | 3+5 = 8 | x++=4 y=5
break

Answer 3

zemiak
Anhjje 🐑
Thank you so much! i finally knew it.!