Answer 1

● take a variable larMod for holding largest modulus value & initialize it with 0
● learn loop for Ai (i varies from 1 to n-1(that is 79 here)) [n>=2] & in each iteration, take out value of |Ai-A(i+1)| & compare its value with larMod, if its larger than larMod, then larMod=|Ai-A(i+1)|
//similiar way you can find smallest modulus of difference b/w adjacent elements [do it in the same loop, initialize & declare one more variable smlMod with larMod]