Can anyone help me with with this enumerations..

Question

enum{
MANGO=5,
BANANA=4,
PEACH
};
printf("%d",peach);
Options are given below..
A) 3
B) 0
C) compilation error
D) 5

Answer 1

Each value in an enum is the value of the preceding element + 1. If you don't assign any values to the elements, they are numbered starting from 0:

enum {
A,
B,
C = 5,
D,
E = 14
};

Here, A will be 0, B will be 1, C will be 5, D will be 6 and E will be 14

Answer 2

Naveen Maurya is right but if you had used Peach in the print the answer would be 5 as it immediately follows Banana in the enumeration which has a value of 4.

Answer 3

Thanks Anna..i got it..😊😊

Answer 4

I guess it leads to an error (C) as enumerations should be case-sensitive.

Answer 5

Sonic, is that true? I did not know that.

Answer 6

Yep..Am sorry guys ... They're all in upper case...

Answer 7

Sonic,yep ur answer is correct.
Can u explain in detail...please...
As peach is not assigned to any value,it should return an error.. isn't it ...

Answer 8

Still a compilation error since you cannot use a ; inside an enum

Answer 9

Anna,now it's correct..what about the explanation of output..