list1=[1,2]?

Question

list 1 = [1,2]
list 2 = list 1
list 3 = list 2 [:]
a = list 2 is list 1
b = list 3 is lis 1
print (a,b)
Output: True False

#First off, it's a single equal sign, so why are they using boolean logic?
#list 2 = list 1 so [1, 2] = [1, 2]. Okay, this checks out.
#list 3 = list 2 [:]? So list three, equals list two with a slice to indicate the first number is blank (which means zero index?) to the highest second number (which would be two)? So they are unequal because [1, 2] != [0, 2]? AHHHHHHH!!!!! This one really confused me. Any help appreciated.

Answer 1

The is keyword returns true if not only they share the same value/object, but share the same id.

list2 is a direct "copy" (don't know if it's the right word for it, a reference perhaps explains it better?) thus:
a = list2 is list1 # a value is: True

list2[:] returns a new list with all the items of two, not the "same list".
Thus:
b = list3 is list1 # b value is: False

That is why output is False.

I wish you success!