What is the output of below code of C++ and give its logic

Question

#include <iostream>
using namespace std;
int main()
{
int a=5,b=7;
char c='D',d='a';
cout<<"\n"<<a<<"##"<<a++<<"##"<<++a;
cout<<"\n"<<++b<<"&&"<<b++<<"&&"<<b+1;
cout<<"\n"<<--c<<"@@"<<c<<"@@"<<c--;
cout<<"\n"<<++d<<"$"<<d++<<"$"<<++d;
return 0;
}

Answer 1

I tell you the logic for only first line
"/n" for new line
a = 5
##
a++ = 5 // but it chages the value of intaitial a to 6
##
++a = 7
as a = 6 before
The ++a increment both new and old value
The final answer for the first line is
5##5##7

Answer 2

If you not understand it go back and read the concept of increment and descrement operators

Answer 3

Sorry your answer is wrong as it is showing some other answer while compiling it

Answer 4

https://code.sololearn.com/c5dx79XNNrpD/?ref=app

Answer 5

I just give you answer for the first and it's correct
5##5##7
For first line answer