What is the output of this code?

Question

for(int i=0; i<10; i++){
if(i&1){
cout<<i;
}}

Answer 1

It will print all odd numbers in the range 0-10 in a row => 13579.

i & 1 is a bitwise operation. It will check if i's last bit is 1, which is only true for odd numbers.

Answer 2

Just put it in the code playground and run to get the output, unless you want an explanation of how the code works