Answer 1

it's a rhombus (the first asterisk is misplaced in the question)
well a good way to learn is try posting ur attempted solution and let others correct it rather than giving the answer itself
hint: use a loop for spaces and for stars

Answer 2

space+stars+space=total column count
2+1+2=5, row 0
1+3+1=5, row 1
0+5+0=5, row 2
1+3+1=5, row 3
2+1+2=5, row 4

n is 5
variable numSpaces initialized to 2
numStars in each iteration = n-2*numSpaces
after each iteration, numSpaces-- (if it's -ive, just multiply by -1)

int n=5;
int numSpaces = 2; /* n/5? */
for (int row=0; row<n; row++)
{
for(int m=0;m<numSpaces;m++)
{
cout<<" ";
}
etc, can u try writing the rest, it's painful to type on mobile lol :p

Answer 3

your welcome

Answer 4

about ur question of nested loops, maybe some clever string manipulation and all might be able to achieve it, I don't know, will have to rattle too much brains :p

Answer 5

lol u r over-studying :p
ah but extra studying never hurts, as long as u hv done the actual studying first :)
best of luck for ur test tmrow

Answer 6

I just googled, and they used 2 iterations, one where no of stars is increasing, and then another separate one where it's decreasing

Answer 7

I think this should work...

#include <iostream>
using namespace std;

int main(){
int n=5;
int numSpaces=n/2;
for(int row=0; row<n; row++)
{

int positiveSpaces = (numSpaces<0)? numSpaces*(-1): numSpaces;

for(int m=0; m<positiveSpaces; m++)
cout<<" ";

for(int m=0; m<n-2*positiveSpaces; m++)
cout<<"*";

numSpaces--;
cout<<"\n";

}//For row

}//main