Can someone please explain this code?

Question

def f(x):
return g(x)+3%2
def g(x):
return x**2+2
print (f(g(1)))

Answer 1

- The function g() takes a parameter x and returns the value x**2+2 ( For example, if x is 1..1**2+2 = 3). Thus, g(1) = 3
- Now, f(g(1)) becomes f(3).
- The function f() also takes a parameter x ( here , x = 3) and returns the value of g(x) + 3%2
g(x) = g(3) = 11.
g(x) + 3%2 now becomes => g(3) + 3%2 = 11 + 3%2 = 11 + 1 = 12
Therefore, it prints 12.

Answer 2

You have two defined functions here and a main body of your programm. The body states:
print(f(g(1))) - it means it calls defined function g() with argument 1 and gets 1**2+2 = 3 in return. Then this result is passed to another function (f()):
return g(3) + 3%2.
Here function g() isa called again with argument 3 and returns 3**2+2 = 11. so now we have a simple equation:
11+3%2 = 11 + 1 = 12

Answer 3

Thank you so much for clearing my doubt.