How can I make this code true??

Question

https://code.sololearn.com/WussqU2vr8ii/?ref=app

Answer 1

Like this:
https://code.sololearn.com/WmJQ6fNOU9u0

Answer 2

l1 is the list of characters to check against str.value[i]. indexOf returns -1 on failure to find the character or the index within the list so 0 or greater.

Answer 3

There are definitely things that try to convince you of that. However, eventually it makes sense and, when those types of new concepts attempt to confuse you, you go: oh..., yeah that makes sense. I just had one of those moments in Kotlin generics. About 5 minutes of what? Before, right! dawned. Just forge ahead you'll get there.

Answer 4

it isn't legal to test a char against a list. If JS had an in operation like other languages, we could do: if(str.value[i] in l1). However, JS's in only verifies properties of the object.

Answer 5

variable names cannot be numbers, also you can't assign multiple values like you tried to do with multiple "=" symbols. rather i suggest making each variable an array of characters and checking if which one the current character belongs to

Answer 6

Right on right on

Answer 7

Every time that I read programming it gets harder😥

Answer 8

and why did you write if(l1.indexOf(str.value[i]) >= 0)
I don't underestand that

Answer 9

Can we write another if.. here
e.g:if(str.value[i] == l1){score++}