Would you tell me why the output of this code is 5?

Question

for(;i<5;i++){
i*=i;
}
System.out.println(i);
}

Answer 1

When the loop starts, i is 0. Now, 0*0=0, and i remains 0. Then, i is incremented by 1.

In the second iteration, 1*1=1, and there is an incrementation, so i becomes 2.

In the third iteration, i first becomes 4 (2*2), and then becomes 5, due to the increment.

In the fourth iteration, i is equal to 5, and the loop terminates.

Thus, you get i == 5.

Answer 2

Can you show the complete code? Did you initialize i prior to the loop?

Answer 3

I initialize i = 0

Answer 4

Kinshuk Vasisht

Answer 5

thank you Kinshuk Vasisht